Chapter 5 - Untitled
Monday, 1 January 0001 | |
3-minute read | |
467 words | |
Optimization
- Assign symbols to all given quantities and quantities to be determined. Make a sketch (if possible).
- Write a PRIMARY EQUATION for the quantity being maximized or minimized. (Call this M.)
- Reduce the primary equation to one having a single independent variable.
- Determine the maximum/minimum using critical values.
- Use the first (or second) derivative test and choose the feasible answer.
- Be sure to answer the question asked. Include units (if applicable).
Example 1
Let the sum of two numbers equal to 16. What are those values that yield the greatest product (maximum)?
$a + b = 16$
$\frac{d}{db}(ab) = 0$
$a = 16 - b$
$(16 - b)(b) = 16b - b^2$
$16 - 2b = 0$
$b = 8$
$a = 8$
Example 3
Example 4
Closest point to $y = 4 - x^2$
$m = \sqrt{x^2 - (2 - x^2)^2}$
$m' = 4x^3 - 6x = 0$
$x = \{ 0, \pm \frac{\sqrt{3}}{2}\}$
Example 5
Find the largest area you can make with 800 meters of wire, open on the top.
$800 = 2x + y$
$m = xy$
$m = x(800 - 2x)$
$m = 800x - 2x^2$
$m' = 800 - 4x$
$m'' = -4$ (this is a minimum)
$m' = -4(x - 200)$
$x = 200$
$800 = 2(200) + y$
$y = 400$
Linearization
If $f$ is differentiable at $x = a$, then the equation of the tangent line, sometimes called $L(x)$, defines the linearization of $f$ at $a$. The approximation is called the linear approximation of $f$ at $a$. The point $x = a$ is called the center of the approximation. Values of $f(x)$ will be "close" to $L(x)$ near the center.
Differentials
Example 1
Let $y = 1 - 2x^2$. Find $dy$ when $x = 1$ and $dx = -0.1$. Compare this value with $\Delta y$ for $x = 1$ and $\Delta x = -0.1$
$\frac{dy}{dx} = -4x$
$dy = -4x \cdot dx$
Related Rates
- Make a sketch (if possible). Name the variables and label the constants on your sketch
- Write down the known information and the variable we are to find
- Write an equation that relates the variables
- Differentiate implicitly the equation with respect to $t$ using the chain rule
- Answer the question that was asked with correct units
Sample AP Question 1
The radius of a circle is increasing at a constant rate of 0.2 meters per second. What is the rate of increase in the area of the circle at the instant when the circumference of the circle is $20\pi$ meters?
\[ C = 20\pi \]
\[ \frac{dr}{dt} = 0.2 \]
\[ C = 20\pi = 2\pi r \]
\[ 20\pi = 2\pi r, r = 10 \]
\[ A = \pi r^2 \]
\[ \frac{dA}{dt} = 2\pi r \frac{dr}{dt} = 2\pi (10)(0.2) = 4\pi \]